Practice Circular Motion MCQs for Bahria University Entry Test Physics — topic-wise sets with solved answers.
Q1. A particle moves in a circular path with constant speed. What is the direction of its acceleration?
Answer: Towards the center
Explanation: The acceleration is centripetal, directed towards the center, given by v² / r, where v is speed and r is radius.
Q2. A car moves around a circular track of radius 50 m at a speed of 20 m/s. What is its centripetal acceleration?
Answer: 8 m/s²
Explanation: Centripetal acceleration = v² / r = (20)² / 50 = 400 / 50 = 8 m/s².
Q3. A particle is moving in a circular path with a radius of 2 m and a constant speed of 4 m/s. What is its angular velocity?
Answer: 2 rad/s
Explanation: Angular velocity (ω) = v / r = 4 / 2 = 2 rad/s.
Q4. The time period of a particle moving in a circular path is 2 s. What is its frequency?
Answer: 0.5 Hz
Explanation: Frequency = 1 / Time period = 1 / 2 = 0.5 Hz.
Q5. A body is moving in a circular path with a constant angular velocity. What is the direction of its linear velocity?
Answer: Tangential to the circle
Explanation: Linear velocity is tangential to the circular path.
Q6. A particle is moving in a circular path with a radius of 1 m and an angular velocity of 3 rad/s. What is its linear speed?
Answer: 3 m/s
Explanation: Linear speed (v) = r * ω = 1 * 3 = 3 m/s.
Q7. The angular displacement of a particle moving in a circular path is π/2 rad in 1 s. What is its angular velocity?
Answer: π/2 rad/s
Explanation: Angular velocity (ω) = Angular displacement / Time = (π/2) / 1 = π/2 rad/s.
Q8. A car is moving around a circular track of radius 100 m at a speed of 25 m/s. What is its centripetal acceleration?
Answer: 6.25 m/s²
Explanation: Centripetal acceleration = v² / r = (25)² / 100 = 625 / 100 = 6.25 m/s².
Q9. A particle is moving in a circular path with a constant speed. What is the work done by the centripetal force?
Answer: Zero
Explanation: Work done by centripetal force is zero as it is perpendicular to the displacement.
Q10. A body is moving in a circular path with a radius of 4 m and a constant speed of 8 m/s. What is its angular speed?
Answer: 2 rad/s
Explanation: Angular speed (ω) = v / r = 8 / 4 = 2 rad/s.
Q11. The frequency of a particle moving in a circular path is 0.5 Hz. What is its time period?
Answer: 2 s
Explanation: Time period = 1 / Frequency = 1 / 0.5 = 2 s.
Q12. A particle is moving in a circular path with a radius of 3 m and an angular velocity of 2 rad/s. What is its linear acceleration?
Answer: 12 m/s²
Explanation: Linear acceleration = r * ω² = 3 * (2)² = 3 * 4 = 12 m/s².
Q13. A body is moving in a circular path with a constant angular acceleration. What is the direction of its angular velocity?
Answer: Along the axis of rotation
Explanation: Angular velocity is along the axis of rotation, following the right-hand rule.
Q14. A particle is moving in a circular path with a radius of 2 m and a speed of 6 m/s. What is its centripetal acceleration?
Answer: 18 m/s²
Explanation: Centripetal acceleration = v² / r = (6)² / 2 = 36 / 2 = 18 m/s².
Q15. A car moves around a circular track of radius 200 m at a speed of 40 m/s. What is its angular speed?
Answer: 0.2 rad/s
Explanation: Angular speed (ω) = v / r = 40 / 200 = 0.2 rad/s.
Q16. The angular velocity of a particle moving in a circular path is 4 rad/s. What is its angular displacement in 2 s?
Answer: 8 rad
Explanation: Angular displacement = ω * t = 4 * 2 = 8 rad.
Q17. A body is moving in a circular path with a radius of 5 m and a constant speed of 15 m/s. What is its centripetal acceleration?
Answer: 45 m/s²
Explanation: Centripetal acceleration = v² / r = (15)² / 5 = 225 / 5 = 45 m/s².
Q18. A particle is moving in a circular path with a constant angular velocity. What is the torque acting on it?
Answer: Zero
Explanation: Torque is zero as there is no angular acceleration.
Q19. A car is moving around a circular track of radius 150 m at a speed of 30 m/s. What is its angular speed?
Answer: 0.2 rad/s
Explanation: Angular speed (ω) = v / r = 30 / 150 = 0.2 rad/s.
Q20. A particle is moving in a circular path with a radius of 1 m and an angular acceleration of 2 rad/s². What is its tangential acceleration?
Answer: 2 m/s²
Explanation: Tangential acceleration = r * α = 1 * 2 = 2 m/s².
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