Practice Partial Fractions MCQs for COMSATS Entry Test Mathematics — topic-wise sets with solved answers.
Q1. Resolve (x + 1) / (x² + 1) into partial fractions.
Answer: 1 / (x + i) + 1 / (x - i)
Explanation: Use formula for partial fraction decomposition with irreducible quadratic factors: (x + 1) / (x² + 1) = A(x - i) + B(x + i).
Q2. The partial fraction decomposition of 1 / (x - 1)(x + 2) is
Answer: 1/3(x - 1) - 1/3(x + 2)
Explanation: Apply formula for partial fraction decomposition with distinct linear factors: 1 / (x - 1)(x + 2) = A/(x - 1) + B/(x + 2).
Q3. Resolve 3x / (x - 1)(x + 2) into partial fractions.
Answer: 1/(x - 1) + 2/(x + 2)
Explanation: Use partial fraction decomposition: 3x / (x - 1)(x + 2) = A/(x - 1) + B/(x + 2), then equate coefficients.
Q4. The value of A in the partial fraction decomposition of 1 / (x - 2)²(x + 1) = A/(x - 2) + B/(x - 2)² + C/(x + 1) is
Answer: -1/9
Explanation: Clear fractions, then equate coefficients to find A: 1 = A(x - 2)(x + 1) + B(x + 1) + C(x - 2)².
Q5. Resolve (x² + 1) / (x + 1)(x² + 4) into partial fractions.
Answer: 2/5(x + 1) + (3x - 2)/5(x² + 4)
Explanation: Use partial fraction decomposition with distinct linear and irreducible quadratic factors.
Q6. The partial fraction decomposition of (x + 2) / (x² - 4) is
Answer: 1/4(x - 2) + 1/4(x + 2)
Explanation: First factor denominator, then apply partial fraction decomposition: (x + 2) / (x - 2)(x + 2) = A/(x - 2) + B/(x + 2).
Q7. The value of B in 1 / (x - 1)²(x + 2) = A/(x - 1) + B/(x - 1)² + C/(x + 2) is
Answer: 1/3
Explanation: Clear fractions and substitute x = 1 to find B: 1 = B(1 + 2).
Q8. Resolve 2x / (x + 1)(x² + 1) into partial fractions.
Answer: -1/(x + 1) + (x + 1)/(x² + 1)
Explanation: Partial fractions: 2x/((x+1)(x²+1)) = -1/(x+1) + (x+1)/(x²+1) after solving for constants.
Q9. The partial fraction decomposition of 1 / (x + 1)(x + 2)(x + 3) is
Answer: 1/2(x + 1) - 1/(x + 2) + 1/2(x + 3)
Explanation: Apply partial fraction decomposition with distinct linear factors: 1 / (x + 1)(x + 2)(x + 3) = A/(x + 1) + B/(x + 2) + C/(x + 3).
Q10. Resolve (2x + 1) / (x - 1)(x + 2) into partial fractions.
Answer: 1/(x - 1) + 1/(x + 2)
Explanation: Let (2x+1)/((x-1)(x+2)) = A/(x-1)+B/(x+2). Solving gives A=1 and B=1.
Q11. The partial fraction decomposition of x / (x² + 2x + 1) is
Answer: 1/(x + 1) - 1/(x + 1)²
Explanation: First factor denominator, then apply partial fraction decomposition: x / (x + 1)² = A/(x + 1) + B/(x + 1)².
Q12. The value of C in 1 / (x - 1)(x + 1)² = A/(x - 1) + B/(x + 1) + C/(x + 1)² is
Answer: -1/2
Explanation: Substitute x = -1 in the cleared equation: 1 = C(-2), so C = -1/2.
Q13. Resolve (x + 3) / (x + 1)(x² + 4) into partial fractions.
Answer: 1/5(x + 1) + (4 - x)/5(x² + 4)
Explanation: Use partial fraction decomposition with distinct linear and irreducible quadratic factors.
Q14. The partial fraction decomposition of 1 / (x² - 1) is
Answer: 1/2(x - 1) - 1/2(x + 1)
Explanation: First factor denominator, then apply partial fraction decomposition: 1 / (x - 1)(x + 1) = A/(x - 1) + B/(x + 1).
Q15. The value of A in 1 / (x + 2)(x - 1)² = A/(x + 2) + B/(x - 1) + C/(x - 1)² is
Answer: 1/9
Explanation: Substitute x = -2: 1 = 9A, so A = 1/9.
Q16. The partial fraction decomposition of x² / (x + 1)(x + 2) is
Answer: 1 + 4/(x + 2) - 1/(x + 1)
Explanation: First divide, then apply partial fraction decomposition: x² / (x + 1)(x + 2) = 1 + A/(x + 1) + B/(x + 2).
Q17. Resolve (x + 2) / (x² + 4x + 4) into partial fractions.
Answer: 1/(x + 2) + 0/(x + 2)²
Explanation: (x+2)/(x+2)² simplifies to 1/(x+2).
Q18. The partial fraction decomposition of 1 / (x + 1)(x² + 2x + 1) is
Answer: 1/(x+1)³
Explanation: Denominator factors as (x+1)³, so the fraction equals 1/(x+1)³.
Q19. Resolve (2x + 3) / (x² - 4) into partial fractions.
Answer: 7 / 4(x - 2) + 1 / 4(x + 2)
Explanation: Factor denominator as (x - 2)(x + 2), then apply partial fractions to get A = 7/4 and B = 1/4.
Q20. The partial fraction decomposition of (x² + 1) / (x + 1)(x - 1) is
Answer: 1 + 1 / (x - 1) - 1 / (x + 1)
Explanation: Divide numerator by denominator to simplify, then apply partial fractions.
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