High Court Clerk / Reader (Lahore / Peshawar) Mathematics Statistics — Set 3

Statistics MCQs set 3 for High Court Clerk / Reader (Lahore / Peshawar) Mathematics — 20 solved questions.

High Court Clerk / Reader (Lahore / Peshawar) Mathematics Statistics — Set 3

  1. Question 1

    Q1. In a frequency distribution, the class with the highest frequency is called the:

    • A) Median class
    • B) Mean class
    • C) Quartile class
    • D) Modal class

    Answer: Modal class

    Explanation: In a frequency distribution the class with the highest frequency is called the modal class, because its value corresponds to the mode.

  2. Question 2

    Q2. The mean of 8, 8, 8, 8, 8 is:

    • A) 0
    • B) 8
    • C) 40
    • D) 5

    Answer: 8

    Explanation: The mean is the sum divided by the count: (8+8+8+8+8)/5 = 40/5 = 8.

  3. Question 3

    Q3. Standard deviation is the square root of:

    • A) Mean
    • B) Range
    • C) Median
    • D) Variance

    Answer: Variance

    Explanation: Variance measures the average squared deviation from the mean; standard deviation is defined as the positive square root of variance.

  4. Question 4

    Q4. The IQR (Interquartile Range) is calculated as:

    • A) Q3 minus Q1
    • B) Q2 minus Q1
    • C) Q3 minus Q2
    • D) Q4 minus Q1

    Answer: Q3 minus Q1

    Explanation: The interquartile range measures the spread of the middle 50% of data, calculated as the third quartile minus the first quartile.

  5. Question 5

    Q5. A histogram is used to display:

    • A) Categorical data only
    • B) Pie chart data
    • C) Frequency distribution of continuous data
    • D) Scatter plots

    Answer: Frequency distribution of continuous data

    Explanation: A histogram uses adjacent bars to display the frequency distribution of continuous (or grouped) quantitative data.

  6. Question 6

    Q6. The value that appears most often in a data set is called:

    • A) Mean
    • B) Median
    • C) Range
    • D) Mode

    Answer: Mode

    Explanation: By definition, the mode is the value that occurs most frequently in a data set.

  7. Question 7

    Q7. The mean of 6 numbers is 12. If one number is removed and the new mean becomes 11, what was the removed number? (Sum was 72, new sum 55, removed = 72-55 = 17)

    • A) 17
    • B) 13
    • C) 15
    • D) 18

    Answer: 17

    Explanation: Original sum = 6 × 12 = 72; after removing one number, new sum = 5 × 11 = 55; so the removed number = 72 − 55 = 17.

  8. Question 8

    Q8. Find the median of: 14, 3, 27, 8, 19, 22. Sorted: 3, 8, 14, 19, 22, 27. Median = (14+19)/2 = 16.5

    • A) 14
    • B) 16.5
    • C) 19
    • D) 17

    Answer: 16.5

    Explanation: Sorting the six values gives 3,8,14,19,22,27; the median of an even set is the mean of the two middle values: (14+19)/2 = 16.5.

  9. Question 9

    Q9. For the data 2, 4, 4, 6, 8, the variance is: Mean=4.8 (sum=24/5). Deviations: -2.8,-0.8,-0.8,1.2,3.2. Squared: 7.84,0.64,0.64,1.44,10.24. Variance = 20.8/5 = 4.16

    • A) 3.36
    • B) 3.84
    • C) 3.96
    • D) 4.16

    Answer: 4.16

    Explanation: With mean = 4.8, the squared deviations are 7.84, 0.64, 0.64, 1.44, and 10.24; their average is 20.8/5 = 4.16.

  10. Question 10

    Q10. The geometric mean of 4 and 16 is:

    • A) 10
    • B) 6
    • C) 9
    • D) 8

    Answer: 8

    Explanation: Geometric mean of two numbers a and b = √(a×b) = √(4×16) = √64 = 8.

  11. Question 11

    Q11. For the data set 5, 10, 15, 20, 25, 30, 35, 40 the Q1 (25th percentile) value is the average of 2nd and 3rd values: (10+15)/2 = 12.5

    • A) 12.5
    • B) 15
    • C) 10
    • D) 20

    Answer: 12.5

    Explanation: For 8 values, Q1 is the average of the 2nd and 3rd values: (10+15)/2=12.5.

  12. Question 12

    Q12. The standard deviation of 2, 4, 4, 4, 5, 5, 7, 9 is: Mean=5, deviations squared sum=32, variance=4, SD=2

    • A) 4
    • B) 3
    • C) 2
    • D) 1

    Answer: 2

    Explanation: With mean = 5 and sum of squared deviations = 32 over 8 values, variance = 32/8 = 4, so standard deviation = √4 = 2.

  13. Question 13

    Q13. In a frequency distribution, the class midpoint is calculated as:

    • A) Upper limit minus lower limit
    • B) (Upper limit plus lower limit) divided by 2
    • C) Lower limit divided by frequency
    • D) Frequency divided by class width

    Answer: (Upper limit plus lower limit) divided by 2

    Explanation: A class midpoint splits the class interval evenly and is calculated as (upper class limit + lower class limit) ÷ 2.

  14. Question 14

    Q14. The harmonic mean of 2 and 8 is: HM = 2/(1/2 + 1/8) = 2/(4/8 + 1/8) = 2/(5/8) = 16/5 = 3.2

    • A) 4
    • B) 5
    • C) 3.2
    • D) 2.5

    Answer: 3.2

    Explanation: The harmonic mean of two numbers a and b is 2ab/(a+b); for 2 and 8: 2×2×8/(2+8)=32/10=3.2.

  15. Question 15

    Q15. In a bar chart showing monthly sales, the height of each bar represents:

    • A) The number of categories
    • B) The time period covered
    • C) The ratio between two variables
    • D) The frequency or value for that category

    Answer: The frequency or value for that category

    Explanation: In a bar chart, the height (or length) of each bar is proportional to the frequency or value it represents for that category.

  16. Question 16

    Q16. If Q1 = 20 and Q3 = 50, the interquartile range (IQR) is:

    • A) 30
    • B) 35
    • C) 25
    • D) 70

    Answer: 30

    Explanation: The interquartile range is Q3 minus Q1: 50 − 20 = 30, measuring the spread of the middle 50% of data.

  17. Question 17

    Q17. Which chart is best for showing parts of a whole as percentages?

    • A) Bar chart
    • B) Histogram
    • C) Pie chart
    • D) Line chart

    Answer: Pie chart

    Explanation: A pie chart divides a circle into sectors whose sizes are proportional to each category's percentage share of the whole.

  18. Question 18

    Q18. The mean of 10 values is 25. Six of those values have a mean of 20. What is the mean of the remaining 4 values? Total sum=250, sum of 6=120, sum of 4=130, mean=130/4=32.5

    • A) 30
    • B) 27.5
    • C) 35
    • D) 32.5

    Answer: 32.5

    Explanation: Total sum = 10×25 = 250; sum of 6 values = 6×20 = 120; remaining sum = 130; mean of 4 = 130/4 = 32.5.

  19. Question 19

    Q19. The data set is 10, 20, 30, 40, 50. The coefficient of variation (CV = SD/Mean x 100) is: Mean=30, Variance=200, SD=√200=14.14, CV=14.14/30 x 100 = 47.14%

    • A) 47.14%
    • B) 33.33%
    • C) 50.00%
    • D) 40.00%

    Answer: 47.14%

    Explanation: Mean=30, variance=[(10-30)²+(20-30)²+(30-30)²+(40-30)²+(50-30)²]/5=200, SD=√200≈14.14, CV=14.14/30×100≈47.14%. 47.14% is correct because it matches what the question requires. Show the calculation clearly when solving similar quantitative items.

  20. Question 20

    Q20. For data 1, 3, 5, 7, 9, 11, 13, what is the interquartile range? Q1=3, Q3=11, IQR=11-3=8

    • A) 4
    • B) 6
    • C) 10
    • D) 8

    Answer: 8

    Explanation: For the ordered data 1,3,5,7,9,11,13: Q1 = 3 and Q3 = 11, so IQR = Q3−Q1 = 11−3 = 8.

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Level 1

In a frequency distribution, the class with the highest frequency is called the: