NTS FBR Tax Facilitation Mathematics: Geometry MCQs

Practice Geometry MCQs for NTS FBR Tax Facilitation Mathematics — topic-wise sets with solved answers.

NTS FBR Tax Facilitation Mathematics: Geometry MCQs — sample questions

  1. Question 1

    Q1. What is the radius of a basketball with a volume of approximately 6400 cm³?

    • A) 10.52 cm
    • B) 11.52 cm
    • C) 12.52 cm
    • D) None of these

    Answer: 11.52 cm

    Explanation: The correct value is 11.52 cm. Apply the formula or arithmetic step shown in the question and

  2. Question 2

    Q2. A rectangular carpet has an area of 60 sq.m its diagonal and longer side together equal 5 times the shorter side. The length of the carpet is:_________?

    • A) 5m
    • B) 12m
    • C) 13m
    • D) 14.5m

    Answer: 12m

    Explanation: Testing l = 12, w = 5: area = 60 ✓, diagonal = 13, and 13 + 12 = 25 = 5 × 5 ✓; length = 12 m.

  3. Question 3

    Q3. The length of a hall is (4/3) times its breadth. If the area of the hall be 300 square meters the difference between the length and breadth is__________?

    • A) 15m
    • B) 4m
    • C) 3m
    • D) None of these

    Answer: None of these

    Explanation: The correct value is None of these. Apply the formula or arithmetic step shown in the question and

  4. Question 4

    Q4. A rectangular field has dimensions 25m by 15m. Two mutually perpendicular passage of 2m width have been left in it's central part and grass has been grown in rest of the field. The area under the grass is____________?

    • A) 295 m²
    • B) 299 m²
    • C) 300 m²
    • D) 375 m²

    Answer: 299 m²

    Explanation: Two perpendicular passages of width 2 m cover: 25×2 + 15×2 − 2×2 = 76 m²; grass area = 375 − 76 = 299 m².

  5. Question 5

    Q5. A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is__________?

    • A) 3.34
    • B) 2
    • C) 4.5
    • D) 5.5

    Answer: 3.34

    Explanation: Inner radius = 2 m, outer = 2.25 m; path area = π(2.25² − 2²) = π × 1.0625 ≈ 3.34 m².

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