Thermodynamics MCQs set 3 for Army Medical College (AMC) Entry Test Physics — 20 solved questions.
Q1. For an adiabatic expansion of an ideal gas, which quantity remains constant?
Answer: PV^\gamma
Explanation: In adiabatic process, PV^\gamma = constant. Entropy is not exactly constant but for ideal gas it is.
Q2. A refrigerator's coefficient of performance is 4. How much heat is removed from the cold body if 100 J work is done?
Answer: 400 J
Explanation: COP = Q_c / W, so Q_c = COP * W = 4 * 100 = 400 J. Other options misinterpret COP or work done.
Q3. A system undergoes a cyclic process. What is the net change in internal energy?
Answer: Zero
Explanation: In a cyclic process, \Delta U = 0 because initial and final states are the same.
Q4. For a given isothermal compression, which of the following is true?
Answer: Work done on the system is positive
Explanation: In compression, work is done on the system, so it's positive. Internal energy doesn't change in isothermal process.
Q5. The entropy change of a free expansion is
Answer: Positive
Explanation: In free expansion, entropy increases because disorder increases. Other options misinterpret entropy change.
Q6. A Carnot engine operates between 800K and 400K. What is its efficiency?
Answer: 50%
Explanation: Efficiency = 1 - (T_cold/T_hot) = 1 - (400/800) = 0.5 or 50%. Other options are wrong temperatures or calculations.
Q7. The molar specific heat at constant volume for a monatomic gas is
Answer: (3/2)R
Explanation: For monatomic gas, C_v = (3/2)R. Other options are specific heats for different types of gases.
Q8. A gas is compressed adiabatically. What happens to its temperature?
Answer: Increases
Explanation: In adiabatic compression, temperature increases because work done on the system increases its internal energy.
Q9. The first law of thermodynamics is a statement of
Answer: Conservation of energy
Explanation: First law, \Delta U = Q - W, represents conservation of energy. Other options are unrelated conservation laws.
Q10. For an ideal gas, the internal energy during an isothermal expansion
Answer: Remains constant
Explanation: Internal energy of ideal gas depends only on temperature, which remains constant in isothermal process.
Q11. A heat pump operates between 250K and 300K. What is its coefficient of performance?
Answer: 6
Explanation: COP = T_hot / (T_hot - T_cold) = 300 / (300 - 250) = 6. Other options misinterpret COP formula or temperatures.
Q12. In a thermodynamic process, the work done by the gas is 200 J and the heat supplied is 300 J. What is the change in internal energy?
Answer: 100 J
Explanation: \Delta U = Q - W = 300 - 200 = 100 J. Other options misapply the first law.
Q13. A thermodynamic system undergoes an isobaric expansion. What remains constant?
Answer: Pressure
Explanation: In isobaric process, pressure remains constant. Other options change during isobaric expansion.
Q14. The change in entropy for a reversible adiabatic process is
Answer: Zero
Explanation: For reversible adiabatic process, \Delta S = 0 because it's isentropic. Other options misinterpret entropy change.
Q15. A thermodynamic process occurs in which the volume remains constant. What type of process is this?
Answer: Isochoric
Explanation: Isochoric process is one where volume remains constant. Other options are different types of thermodynamic processes.
Q16. Why does the temperature of a gas remain constant during an isothermal expansion?
Answer: Because heat is absorbed by the gas
Explanation: Heat is absorbed, maintaining constant temperature; 'ideal gas' is a property, not the reason for constant temperature.
Q17. In an adiabatic compression, what happens to the internal energy of the gas?
Answer: It increases
Explanation: Internal energy increases due to work done on the gas; no heat transfer occurs in adiabatic processes.
Q18. A refrigerator transfers heat from a cold body to a hot body. Which law of thermodynamics does this process violate if there is no external work?
Answer: Second Law
Explanation: Second Law is violated as spontaneous heat transfer from cold to hot is impossible without external work.
Q19. What is the primary function of a heat engine's 'sink'?
Answer: To absorb excess heat from the engine
Explanation: The sink absorbs excess heat, allowing the engine to operate in a cycle; it doesn't supply heat or do work.
Q20. Why can't a real heat engine achieve 100% efficiency?
Answer: Because it violates the Second Law
Explanation: 100% efficiency violates the Second Law; friction and heat loss are practical limitations, not the fundamental reason.