MDCAT Physics MCQ #3407

A refrigerator's coefficient of performance is 4. How much heat is removed from the cold body if 100 J work is done?

MDCAT Physics MCQ #3407

  1. Question 1

    Q1. A refrigerator's coefficient of performance is 4. How much heat is removed from the cold body if 100 J work is done?

    • A) 400 J
    • B) 500 J
    • C) 300 J
    • D) 200 J

    Answer: 400 J

    Explanation: COP = Q_c / W, so Q_c = COP * W = 4 * 100 = 400 J. Other options misinterpret COP or work done.