Practice Electrostatics MCQs for Pharm-D Entry Test (D Pharmacy) Physics — topic-wise sets with solved answers.
Q1. The unit of electric field intensity in SI system is
Answer: N/C
Explanation: Electric field intensity is measured in N/C; V/m is equivalent but not the primary unit. C/N is incorrect.
Q2. Coulomb's law is applicable to
Answer: Point charges
Explanation: Coulomb's law applies to point charges; it can be extended to larger objects with certain assumptions.
Q3. The electric potential at a point due to a point charge is given by
Answer: kQ/r
Explanation: Electric potential due to a point charge is kQ/r; kQ/r^2 is the electric field, not potential.
Q4. The capacitance of a capacitor depends upon
Answer: Geometry of capacitor
Explanation: Capacitance depends on geometry; charge and potential difference are related but not the primary factors.
Q5. A capacitor is charged by a battery. The battery is removed and a dielectric slab is inserted. What happens to the charge?
Answer: Remains the same
Explanation: Charge remains the same as battery is removed; dielectric affects capacitance and potential difference.
Q6. The electric flux through a closed surface is proportional to
Answer: Charge enclosed
Explanation: Gauss's law states that flux is proportional to enclosed charge; outside charge doesn't affect total flux.
Q7. Two charges q1 and q2 are placed at a distance r. If the force between them is F, what happens to F if r is doubled?
Answer: F/4
Explanation: Coulomb's law states F ∝ 1/r^2; doubling r reduces F to F/4.
Q8. The SI unit of capacitance is
Answer: Farad
Explanation: Farad is the unit of capacitance; Henry is for inductance, Ohm for resistance, Tesla for magnetic field.
Q9. When a dielectric is inserted between the plates of a capacitor, its capacitance
Answer: Increases
Explanation: Dielectric increases capacitance by reducing electric field between plates.
Q10. The electric field due to a uniformly charged infinite plane sheet is
Answer: σ/2ε₀
Explanation: Electric field due to infinite plane sheet is σ/2ε₀; doesn't depend on distance.
Q11. A charge is placed at the center of a spherical Gaussian surface. The electric flux through the surface is
Answer: q/ε₀
Explanation: Gauss's law states that flux is q/ε₀; depends on enclosed charge, not surface details.
Q12. The potential difference between two points in an electric field is
Answer: Both A and C
Explanation: Potential difference is work done per unit charge, equivalent to energy per unit charge.
Q13. The electric field inside a conductor is
Answer: Zero
Explanation: Inside a conductor, electric field is zero in electrostatic equilibrium.
Q14. The charge on a capacitor is given by
Answer: CV
Explanation: Charge on a capacitor is given by Q = CV; relates capacitance, charge, and potential difference.
Q15. A capacitor is connected to a battery. A dielectric slab is inserted. What happens to the potential difference?
Answer: Remains the same
Explanation: Potential difference remains the same as battery maintains it; dielectric affects capacitance.
Q16. The electric potential due to a dipole at a point on its axis is
Answer: k2p/r^3
Explanation: Potential due to dipole on its axis is k2p/r^3; depends on dipole moment and distance.
Q17. The force between two charges is F. If a third charge is introduced between them, the force between the original two charges
Answer: Remains the same
Explanation: Introducing a third charge doesn't affect the force between the original two; superposition principle applies.
Q18. The surface charge density on a conductor is
Answer: Proportional to electric field
Explanation: Surface charge density is proportional to electric field just outside; related through ε₀.
Q19. The energy density in an electric field is given by
Answer: 1/2 ε₀E^2
Explanation: Energy density in electric field is 1/2 ε₀E^2; relates energy stored to field strength.
Q20. A point charge of 2 μC is placed 0.5 m away from another point charge of -3 μC. What is the magnitude of the electrostatic force between them?
Answer: 0.216 N
Explanation: Coulomb's Law gives F = k * q1 * q2 / r^2 = 0.216 N. Wrong options are due to incorrect unit conversions.
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