Two charges q1 and q2 are placed at a distance r. If the force between them is F, what happens to F if r is doubled?
Q1. Two charges q1 and q2 are placed at a distance r. If the force between them is F, what happens to F if r is doubled?
Answer: F/4
Explanation: Coulomb's law states F ∝ 1/r^2; doubling r reduces F to F/4.