For the reaction N2 + 3H2 ⇌ 2NH3, if the equilibrium constant Kc is 4, what is Kp at 27°C?
Q1. For the reaction N2 + 3H2 ⇌ 2NH3, if the equilibrium constant Kc is 4, what is Kp at 27°C?
Answer: 4 × (0.0821 × 300)^-2
Explanation: Kp = Kc(RT)^Δn, Δn = 2 - 4 = -2, so Kp = 4 × (0.0821 × 300)^-2