For the reaction A + B ⇌ C + D, Kc = 4. If 1 mole of A and 1 mole of B are mixed, what is the equilibrium concentration of C?
Q1. For the reaction A + B ⇌ C + D, Kc = 4. If 1 mole of A and 1 mole of B are mixed, what is the equilibrium concentration of C?
Answer: 2/3
Explanation: Kc = [C][D]/[A][B] = 4, let x be the concentration of C, then x²/(1-x)² = 4, x = 2/3