The equilibrium constant for the reaction H2 + I2 ⇌ 2HI is 50 at 700K. What is the value of Kc for HI ⇌ 1/2H2 + 1/2I2?
Q1. The equilibrium constant for the reaction H2 + I2 ⇌ 2HI is 50 at 700K. What is the value of Kc for HI ⇌ 1/2H2 + 1/2I2?
Answer: 1/√50
Explanation: When the reaction is halved and reversed, Kc becomes 1/√Kc, so Kc = 1/√50