For the reaction N2 + O2 ⇌ 2NO, if the equilibrium constant Kc is 4 × 10^-4 at 2000K, what is the value of Kc for NO ⇌ 1/2N2 + 1/2O2?
Q1. For the reaction N2 + O2 ⇌ 2NO, if the equilibrium constant Kc is 4 × 10^-4 at 2000K, what is the value of Kc for NO ⇌ 1/2N2 + 1/2O2?
Answer: 1/√(4 × 10^-4)
Explanation: When the reaction is halved and reversed, Kc becomes 1/√Kc, so Kc = 1/√(4 × 10^-4)