The value of Kc for the reaction A ⇌ 2B is 4. If the initial concentration of A is 1 M, what is [B] at equilibrium?
Q1. The value of Kc for the reaction A ⇌ 2B is 4. If the initial concentration of A is 1 M, what is [B] at equilibrium?
Answer: 0.8 M
Explanation: Kc = [B]²/[A], assuming x M of A reacts, 4 = (2x)²/(1-x), solving gives x = 0.4, hence [B] = 2x = 0.8.