For the reaction 2NO ⇌ N2 + O2, if Kc = 0.1 and initial concentration of NO is 2 M, what is [N2] at equilibrium?
Q1. For the reaction 2NO ⇌ N2 + O2, if Kc = 0.1 and initial concentration of NO is 2 M, what is [N2] at equilibrium?
Answer: 0.25 M
Explanation: Kc = [N2][O2]/[NO]², assuming x M of NO reacts, 0.1 = x²/(2-2x)², solving gives x = 0.25 (approx).