For the reaction N2 + 3H2 ⇌ 2NH3, if the equilibrium constant is K, then for NH3 ⇌ 1/2N2 + 3/2H2, K' is
Q1. For the reaction N2 + 3H2 ⇌ 2NH3, if the equilibrium constant is K, then for NH3 ⇌ 1/2N2 + 3/2H2, K' is
Answer: √(1/K)
Explanation: When the reaction is reversed and halved, K' = √(1/K) because the equilibrium constant for the reversed reaction is 1/K and for halved reaction is √K.