engineering chemistry MCQ #2751

For the reaction, 2Cl^- → Cl2 + 2e^-, the electrode potential is -1.36 V. What is the potential when [Cl^-] = 0.1 M?

engineering chemistry MCQ #2751

  1. Question 1

    Q1. For the reaction, 2Cl^- → Cl2 + 2e^-, the electrode potential is -1.36 V. What is the potential when [Cl^-] = 0.1 M?

    • A) -1.42 V
    • B) -1.30 V
    • C) -1.36 V
    • D) -1.48 V

    Answer: -1.42 V

    Explanation: Using Nernst equation, E = E° - 0.0592 / n * log(1 / [Cl^-]²), E = -1.36 - 0.0592 / 2 * log(1 / 0.1²) = -1.36 - 0.0592 = -1.42 V (approx).