The conductivity of a 0.1 M solution of KCl is 1.29 S/m. Calculate the molar conductivity.
Q1. The conductivity of a 0.1 M solution of KCl is 1.29 S/m. Calculate the molar conductivity.
Answer: 12900 S cm²/mol
Explanation: Molar conductivity = conductivity * 1000 / M = 1.29 * 1000 / 0.1 = 12900 S cm²/mol (since 1 S/m = 1 S / 100 cm, 1.29 S/m = 0.0129 S/cm, but here we directly use the given value).