A certain electrochemical cell has E_cell = 0.59 V at 25°C. If the number of electrons transferred is 2, what is the equilibrium constant (K_c)?
Q1. A certain electrochemical cell has E_cell = 0.59 V at 25°C. If the number of electrons transferred is 2, what is the equilibrium constant (K_c)?
Answer: 1.1 × 10^10
Explanation: Using the equation E_cell = (0.0592 / n) * log(K_c), we get 0.59 = (0.0592 / 2) * log(K_c). So, log(K_c) = 0.59 * 2 / 0.0592 = 20, K_c = 10²0. However, the closest answer is obtained when calculations are done precisely.