A conductivity cell filled with 0.1 M KCl has a resistance of 100 Ω. The cell constant is (conductivity of 0.1 M KCl = 1.29 S/m)?
Q1. A conductivity cell filled with 0.1 M KCl has a resistance of 100 Ω. The cell constant is (conductivity of 0.1 M KCl = 1.29 S/m)?
Answer: 129 m^-1
Explanation: Cell constant = conductivity * resistance = 1.29 S/m * 100 Ω = 129 m^-1.