For the cell reaction, 2Fe³⁺ + 2I^- → 2Fe²⁺ + I2, E_cell = 0.236 V at 298 K. Calculate the standard Gibbs free energy change (ΔG°).
Q1. For the cell reaction, 2Fe³⁺ + 2I^- → 2Fe²⁺ + I2, E_cell = 0.236 V at 298 K. Calculate the standard Gibbs free energy change (ΔG°).
Answer: -45.5 kJ
Explanation: ΔG° = -nFE°, n = 2 (electrons transferred), F = 96500 C/mol, E° = 0.236 V, so ΔG° = -2 * 96500 * 0.236 = -45548 J = -45.5 kJ.