For a certain cell, ΔG = -100 kJ at 298 K. If 'n' = 2, what is E_cell?
Question 1
Q1. For a certain cell, ΔG = -100 kJ at 298 K. If 'n' = 2, what is E_cell?
Answer: 0.52 V
Explanation: ΔG = -nFE_cell, so E_cell = -ΔG / nF = 100000 / (2 * 96500) = 0.52 V.