engineering chemistry MCQ #2768

For the cell reaction, Zn + Cu²⁺ → Zn²⁺ + Cu, E_cell = 1.1 V. What is the E° for the Cu²⁺/Cu electrode?

engineering chemistry MCQ #2768

  1. Question 1

    Q1. For the cell reaction, Zn + Cu²⁺ → Zn²⁺ + Cu, E_cell = 1.1 V. What is the E° for the Cu²⁺/Cu electrode?

    • A) +0.34 V
    • B) -0.76 V
    • C) +0.76 V
    • D) -0.34 V

    Answer: +0.34 V

    Explanation: E_cell = E°(cathode) - E°(anode), 1.1 = E°(Cu²⁺/Cu) - (-0.76), so E°(Cu²⁺/Cu) = 1.1 - 0.76 = +0.34 V.