For the cell reaction: 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂, E⁰_cell = 0.236 V at 298 K. The equilibrium constant is
Q1. For the cell reaction: 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂, E⁰_cell = 0.236 V at 298 K. The equilibrium constant is
Answer: 9.69 × 10⁷
Explanation: Using log Kc = nE⁰ / 0.0591, where n = 2, E⁰ = 0.236 V, we get log Kc = 7.987, so Kc = 9.69 × 10⁷.