engineering chemistry MCQ #2772

The conductivity of 0.1 M KCl is 1.29 S / cm. If the resistance of the conductivity cell is 100 Ω, the cell constant is

engineering chemistry MCQ #2772

  1. Question 1

    Q1. The conductivity of 0.1 M KCl is 1.29 S / cm. If the resistance of the conductivity cell is 100 Ω, the cell constant is

    • A) 1.29 cm⁻¹
    • B) 12.9 cm⁻¹
    • C) 0.129 cm⁻¹
    • D) 129 cm⁻¹

    Answer: 12.9 cm⁻¹

    Explanation: Cell constant = conductivity × resistance = 1.29 S / cm × 100 Ω = 129 cm⁻¹.