engineering chemistry MCQ #2778

For the reaction: 2H⁺ + 2e⁻ → H₂, E⁰ = 0 V. The potential at pH = 7 is

engineering chemistry MCQ #2778

  1. Question 1

    Q1. For the reaction: 2H⁺ + 2e⁻ → H₂, E⁰ = 0 V. The potential at pH = 7 is

    • A) -0.413 V
    • B) 0.413 V
    • C) -0.207 V
    • D) 0.207 V

    Answer: -0.413 V

    Explanation: Using Nernst equation, E = E⁰ - 0.0591 / n log(1 / [H⁺]²), at pH = 7, [H⁺] = 10⁻⁷ M.