engineering chemistry MCQ #2788

For the reaction: O₂ + 4H⁺ + 4e⁻ → 2H₂O, E⁰ = 1.23 V. The E at pH = 7 is

engineering chemistry MCQ #2788

  1. Question 1

    Q1. For the reaction: O₂ + 4H⁺ + 4e⁻ → 2H₂O, E⁰ = 1.23 V. The E at pH = 7 is

    • A) 0.82 V
    • B) 0.41 V
    • C) 1.23 V
    • D) 0.0 V

    Answer: 0.82 V

    Explanation: Using Nernst equation, E = E⁰ - 0.0591 / n log(1 / [H⁺]⁴), at pH = 7.