The number of Faradays required to deposit 108 g of Ag from AgNO₃ solution is
Question 1
Q1. The number of Faradays required to deposit 108 g of Ag from AgNO₃ solution is
Answer: 1 F
Explanation: Ag⁺ + e⁻ → Ag, 108 g = 1 mole, so 1F is required.