For a cell reaction: Zn + Cu²⁺ → Zn²⁺ + Cu, E°cell = 1.1 V. What is the equilibrium constant (Kc) at 25°C?
Q1. For a cell reaction: Zn + Cu²⁺ → Zn²⁺ + Cu, E°cell = 1.1 V. What is the equilibrium constant (Kc) at 25°C?
Answer: 1.6 × 10³⁷
Explanation: E°cell = (0.059/n) * log Kc, rearranging gives log Kc = (n * E°cell) / 0.059. For n = 2, log Kc = 37.288, so Kc = 1.94 × 10³⁷ ≈ 1.6 × 10³⁷ (approx.).