engineering chemistry MCQ #2792

The conductivity of 0.01 M KCl solution is 0.0014 S/cm. Calculate the cell constant if the resistance is 1500 Ω.

engineering chemistry MCQ #2792

  1. Question 1

    Q1. The conductivity of 0.01 M KCl solution is 0.0014 S/cm. Calculate the cell constant if the resistance is 1500 Ω.

    • A) 2.1 cm⁻¹
    • B) 1.4 cm⁻¹
    • C) 1.05 cm⁻¹
    • D) 2.5 cm⁻¹

    Answer: 2.1 cm⁻¹

    Explanation: Cell constant = conductivity * resistance = 0.0014 S/cm * 1500 Ω = 2.1 cm⁻¹.