For a reaction: 2H⁺ + 2e⁻ → H₂, the reduction potential at pH = 7 is -0.414 V. What is the standard reduction potential?
Q1. For a reaction: 2H⁺ + 2e⁻ → H₂, the reduction potential at pH = 7 is -0.414 V. What is the standard reduction potential?
Answer: 0 V
Explanation: E = E° - (0.059/n) * log (1 / [H⁺]²), at pH = 7, [H⁺] = 10⁻⁷ M. E = E° - (0.059/2) * log (1 / (10⁻⁷)²), -0.414 = E° - (-0.414), so E° = 0 V.