The molar conductivity of 0.1 M CH₃COOH is 5.2 S cm²/mol. Calculate the degree of dissociation (α).
Q1. The molar conductivity of 0.1 M CH₃COOH is 5.2 S cm²/mol. Calculate the degree of dissociation (α).
Answer: 0.013
Explanation: α = Λm / Λ°m, where Λ°m for CH₃COOH = 390.7 S cm²/mol (approx.), so α = 5.2 / 390.7 = 0.0133 ≈ 0.013.