engineering chemistry MCQ #2795

A conductivity cell contains 0.01 M KCl solution with conductivity 0.0014 S/cm. If the resistance is 100 Ω, what is the cell constant?

engineering chemistry MCQ #2795

  1. Question 1

    Q1. A conductivity cell contains 0.01 M KCl solution with conductivity 0.0014 S/cm. If the resistance is 100 Ω, what is the cell constant?

    • A) 0.14 cm⁻¹
    • B) 1.4 cm⁻¹
    • C) 0.7 cm⁻¹
    • D) 14 cm⁻¹

    Answer: 0.14 cm⁻¹

    Explanation: Cell constant = conductivity * resistance = 0.0014 S/cm * 100 Ω = 0.14 cm⁻¹.