The standard electrode potential for the reaction: Ag⁺ + e⁻ → Ag is +0.80 V. The potential at [Ag⁺] = 0.01 M is
Q1. The standard electrode potential for the reaction: Ag⁺ + e⁻ → Ag is +0.80 V. The potential at [Ag⁺] = 0.01 M is
Answer: +0.68 V
Explanation: E = E° - (0.059/n) * log (1 / [Ag⁺]), E = 0.80 - 0.059 * log (1 / 0.01) = 0.80 - 0.118 = 0.682 V.