For a cell: Pt | H₂ (1 atm) | H⁺ (1 M) || Cu²⁺ (1 M) | Cu, E°cell = +0.34 V. The E° for Cu²⁺/Cu is
Q1. For a cell: Pt | H₂ (1 atm) | H⁺ (1 M) || Cu²⁺ (1 M) | Cu, E°cell = +0.34 V. The E° for Cu²⁺/Cu is
Answer: +0.34 V
Explanation: E°cell = E°(cathode) - E°(anode), E°(anode) = 0 V for SHE, so E°cell = E°(Cu²⁺/Cu) = +0.34 V.