engineering chemistry MCQ #3377

The compressibility factor (Z) for an ideal gas is:

engineering chemistry MCQ #3377

  1. Question 1

    Q1. The compressibility factor (Z) for an ideal gas is:

    • A) 0
    • B) 1
    • C) 2
    • D) -1

    Answer: 1

    Explanation: For ideal gases, PV = nRT, so Z = PV/nRT = 1.