A gas occupies 1 L at 1 atm. What is its volume at 2 atm, if temperature remains constant?
Q1. A gas occupies 1 L at 1 atm. What is its volume at 2 atm, if temperature remains constant?
Answer: 0.5 L
Explanation: Apply Boyle's law: P1V1 = P2V2, so V2 = P1V1 / P2 = 1 * 1 / 2 = 0.5 L.