engineering chemistry MCQ #4897

For the reaction 2NO + O2 -> 2NO2, the rate law is rate = k[NO]²[O2]. If [NO] is doubled and [O2] is halved, the rate

engineering chemistry MCQ #4897

Question 1
Q1. For the reaction 2NO + O2 -> 2NO2, the rate law is rate = k[NO]²[O2]. If [NO] is doubled and [O2] is halved, the rate
- A) doubles
- B) halves
- C) remains same
- D) becomes 2 times
Answer: becomes 2 times
Explanation: New rate = k(2[NO])²([O2]/2) = k(4[NO]²)([O2]/2) = 2k[NO]²[O2], so rate becomes 2 times the original.