The activation energy for a reaction is 80 kJ/mol. At what temperature will the rate be double at 300 K?
Q1. The activation energy for a reaction is 80 kJ/mol. At what temperature will the rate be double at 300 K?
Answer: 310 K
Explanation: Using Arrhenius equation and given that k2 = 2k1, we can find T2 = 310 K, with Ea = 80 kJ/mol and T1 = 300 K.