The rate law for the reaction 2A + B -> C is rate = k[A]²[B]. If [A] is doubled and [B] is halved, the rate will be
Q1. The rate law for the reaction 2A + B -> C is rate = k[A]²[B]. If [A] is doubled and [B] is halved, the rate will be
Answer: quadrupled but then halved, so doubled
Explanation: New rate = k(2[A])²([B]/2) = k(4[A]²)([B]/2) = 2k[A]²[B], so the rate is doubled.