The major product of the reaction between (CH₃)₃CBr and CH₃O⁻ is
Q1. The major product of the reaction between (CH₃)₃CBr and CH₃O⁻ is
Answer: (CH₃)₂C=CH₂
Explanation: Tertiary alkyl halides with strong base (CH₃O⁻) undergo E2 elimination to form alkene.