engineering chemistry MCQ #949

The wavelength of a spectral line in the Lyman series is given by

engineering chemistry MCQ #949

  1. Question 1

    Q1. The wavelength of a spectral line in the Lyman series is given by

    • A) 1 / λ = R * (1 / 1² - 1 / n²)
    • B) 1 / λ = R * (1 / 2² - 1 / n²)
    • C) 1 / λ = R * (1 / 3² - 1 / n²)
    • D) 1 / λ = R * (1 / 4² - 1 / n²)

    Answer: 1 / λ = R * (1 / 1² - 1 / n²)

    Explanation: Lyman series corresponds to transitions to n = 1, so 1 / λ = R * (1 / 1² - 1 / n²).