engineering chemistry MCQ #976

The kinetic energy of an electron in the nth orbit is given by K = 13.6 / n² eV. For n = 2, K will be

engineering chemistry MCQ #976

  1. Question 1

    Q1. The kinetic energy of an electron in the nth orbit is given by K = 13.6 / n² eV. For n = 2, K will be

    • A) 3.4 eV
    • B) 6.8 eV
    • C) 1.7 eV
    • D) 13.6 eV

    Answer: 3.4 eV

    Explanation: Substitute n = 2 into K = 13.6 / n² to get K = 3.4 eV.