engineering chemistry MCQ #978

The frequency of revolution of an electron in the nth orbit is given by f = me⁴ / (4ε₀²n³h³). For n = 1, f will be

engineering chemistry MCQ #978

  1. Question 1

    Q1. The frequency of revolution of an electron in the nth orbit is given by f = me⁴ / (4ε₀²n³h³). For n = 1, f will be

    • A) 6.58 x 10¹⁵ Hz
    • B) 3.29 x 10¹⁵ Hz
    • C) 1.65 x 10¹⁵ Hz
    • D) 0.658 x 10¹⁵ Hz

    Answer: 6.58 x 10¹⁵ Hz

    Explanation: Substitute n = 1 into f = me⁴ / (4ε₀²n³h³) to get f = 6.58 x 10¹⁵ Hz.