engineering chemistry MCQ #989

The ionization energy of H-atom is 13.6 eV. What is the ionization energy of Li²⁺?

engineering chemistry MCQ #989

  1. Question 1

    Q1. The ionization energy of H-atom is 13.6 eV. What is the ionization energy of Li²⁺?

    • A) 13.6 eV
    • B) 54.4 eV
    • C) 122.4 eV
    • D) 13.6 / 9 eV

    Answer: 122.4 eV

    Explanation: Ionization energy is proportional to Z². For Li²⁺, Z = 3, so ionization energy = 13.6 * 3² = 13.6 * 9 = 122.4 eV.