A virtual memory system has 32-bit virtual address, 4KB page size. How many page table entries?
Q1. A virtual memory system has 32-bit virtual address, 4KB page size. How many page table entries?
Answer: 1048576
Explanation: Number of page table entries = 2^(virtual address bits - page offset bits) = 2^(32 - 12) = 2²0 = 1048576.