engineering computer science MCQ #175

A disk has 5000 RPM, average seek time = 5 ms. What is the average access time?

engineering computer science MCQ #175

  1. Question 1

    Q1. A disk has 5000 RPM, average seek time = 5 ms. What is the average access time?

    • A) 10 ms
    • B) 11 ms
    • C) 12 ms
    • D) 8 ms

    Answer: 11 ms

    Explanation: Average rotational latency = 60 / (2 * RPM) = 60 / (2 * 5000) = 6 ms, average access time = average seek time + average rotational latency = 5 + 6 = 11 ms.