engineering computer science MCQ #191

A disk has an average seek time of 5ms, rotation speed of 7200 rpm, and data transfer rate of 100MB/s. What is the average access time?

engineering computer science MCQ #191

  1. Question 1

    Q1. A disk has an average seek time of 5ms, rotation speed of 7200 rpm, and data transfer rate of 100MB/s. What is the average access time?

    • A) 10ms
    • B) 12ms
    • C) 9.17ms
    • D) 8.33ms

    Answer: 9.17ms

    Explanation: Average access time = average seek time + average rotational latency + data transfer time, average rotational latency = 60 / (2 * 7200) = 4.17ms, hence average access time = 5 + 4.17 = 9.17ms (data transfer time is negligible for small data)