What is the efficiency of a protocol that has a throughput of 8000 bps and a data rate of 10000 bps?
Q1. What is the efficiency of a protocol that has a throughput of 8000 bps and a data rate of 10000 bps?
Answer: 0.8
Explanation: Efficiency = Throughput / Data Rate = 8000 / 10000 = 0.8.