A channel has a capacity of 40000 bps and a bandwidth of 5000 Hz. What is its S/N ratio?
Q1. A channel has a capacity of 40000 bps and a bandwidth of 5000 Hz. What is its S/N ratio?
Answer: 15.9
Explanation: Using Shannon-Hartley theorem: C = B * log2(1 + S/N), 40000 = 5000 * log2(1 + S/N), S/N = 2^(40000/5000) - 1 = 15.9.