How many signal levels are required to achieve a data rate of 24000 bps over a 3000 Hz channel?
Q1. How many signal levels are required to achieve a data rate of 24000 bps over a 3000 Hz channel?
Answer: 16
Explanation: Using Nyquist formula: Data Rate = 2 * Bandwidth * log2(L), 24000 = 2 * 3000 * log2(L), log2(L) = 4, L = 2⁴ = 16.